H=-6t^2+6t

Solution for H=-6t^2+6t equation:

=-6H^2+6H

We move all terms to the left:

-(-6H^2+6H)=0

We get rid of parentheses

6H^2-6H=0

a = 6; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·6·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*6}=\frac{0}{12}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*6}=\frac{12}{12}
=1
$